The greatest number that divides 93 and 190 leaving remainders 5 and 3, respectively, is:

Correct option is D

Given:

When dividing 93, remainder = 5

When dividing 190, remainder = 3

We are to find the greatest number that divides both and leaves those remainders.

Solution:

93 − 5 = 88

190 − 3 = 187

Now, HCF of 88 and 187: 

88 = $$2^3\times 11$$​​

187 = $$11\times 17$$​​

So, HCF(88,187) = 11

Thus, the greatest number which divides with given condition is 11.