The graph of y = 9$$x^2$$​+ 16:

Correct option is D

​​Given:

The equation of the graph is:

y = 9x² + 16

Concept Used:

A graph intersects or touches the x-axis where y = 0

Solution:

Putting y = 0:

9x² + 16 = 0

9x² = -16

​$$x^2 = -\frac{16}{9}$$​​

Since x² cannot be negative, there are no real solutions. This means the graph neither intersects nor touches the x-axis.