The given table shows the number of candidates appeared in an interview for different posts (A, B, C, D, E and F).What is the average number of candidates appearing for the posts C, D, E and F?

Posts	Candidates appearing
A	5500
B	8200
C	8600
D	9900
E	5300
F	5100

Correct option is C

Given:

C = 8600

D = 9900

E = 5300

F = 5100

Concept Used:

​$$\text{Average} = \frac{\text{Sum of all values}}{\text{Number of values}}$$​

Solution:

Sum of candidates appearing for posts C, D, E, and F:

8600 + 9900 + 5300 + 5100 = 28900

Number of posts considered = 4

​$$\text{Average} = \frac{28900}{4} = 7225$$​