Correct option is B
Solution:
Sum of marks of each students;
A = (48 + 47 + 49 + 46 + 44) = 234
B = 29 + 33 + 22 + 15 + 30 = 129
C = 35 + 36 + 42 + 40 + 29 = 182
D = 46 + 49 + 48 + 48 + 40 = 231
E = 32 + 30 + 25 + 21 + 22 = 130
Percentage of A (who has the maximum marks)
=
= 93.60%





