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The distance travelled by an object in time 't' is given byx=a+bt+ct2 x = a + bt + ct^2x=a+bt+ct2​ . Identify ‘c’.
Question

The distance travelled by an object in time 't' is given byx=a+bt+ct2 x = a + bt + ct^2​ . Identify ‘c’.

A.

Velocity

B.

Acceleration

C.

Speed

D.

Distance

Correct option is B

The correct answer is: (b) Acceleration

Explanation:
The equation given is x=a+bt+ct2x = a + bt + ct^2x=a+bt+ct2, which describes the displacement x of an object as a function of time t. In this equation:

  • a represents the initial position.

  • b represents the initial velocity.

  • c is the coefficient that represents the acceleration of the object.

This is because the term ct2ct^2ct2 is related to the displacement due to acceleration. In kinematic equations, displacement is typically expressed as a function of time squared, where the coefficient of t2t2 is directly proportional to the acceleration.

Information Booster:

  • Velocity and Acceleration: In motion equations, the velocity is the rate of change of displacement with time, and the acceleration is the rate of change of velocity with time. The coefficient b represents the initial velocity, and c is the acceleration.

  • Kinematic Equation: The general form of the kinematic equation is x=x0+v0t+12at2,x = x_0 + v_0t + \frac{1}{2}at^2, ​where x0x_0 is the initial position, v0v_0v0 is the initial velocity, and aa is the acceleration. In this case, c12a\frac{1}{2}a​ plays the same role as in the standard kinematic equation.

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