The digit in place of A that makes 25432A7 divisible by 9 is:
Given:
Number = 25432A7
We need digit A such that the number is divisible by 9.
Concept Used:
A number is divisible by 9 if the sum of its digits is divisible by 9.
Solution :
2 + 5 + 4 + 3 + 2 + A + 7 = 23 + A
Now, find a digit A (0–9) such that 23 + A is divisible by 9.
Multiples of 9 near 23 are: 18, 27, 36 …
The next multiple of 9 after 23 is 27.
23 + A = 27
A = 4
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