The compound interest on a sum of ₹ 15000 at 4% per annum for 3 years compounded annually is

Correct option is B

Given
Principal (P) = ₹ 15000
Rate (R) = 4% p.a.
Time (n) = 3 years

Formula Used
Amount =  $$P(1 + \frac{R}{100})^n$$​

Compound Interest (CI) = Amount - Principal

Solution
Amount =  $$15000 \times (1 + \frac{4}{100})^3$$​​
Amount =  $$15000 \times (1.04)^3 = 15000 \times 1.124864$$​​
Amount = 16872.96
CI = 16872.96 - 15000 = 1872.96

Final Answer
So the correct answer is (b)