The compound interest on ₹2,000 for one year at 10% per annum, compounded half-yearly, is

Correct option is C

Given:
Principal (P) = ₹2000
Time (T) = 1 year
Annual Rate (R) = 10%
Compounding frequency = half-yearly
Formula Used:
Amount = $$P(1 + \frac{R/2}{100})^{2T}$$​​
Compound Interest (CI) = Amount - P
Solution:
For half-yearly compounding, the rate is halved and time periods are doubled.
Rate per period = $$\frac{10}{2} = 5\%$$​​
Number of periods = 1 × 2 = 2 half-years.
Amount = $$2000 × (1 + \frac{5}{100})^2$$​​
 = $$2000 × (1.05)^2$$​​
 = 2000 × 1.1025 = 2205
Compound Interest = 2205 - 2000 = 205.
Final Answer
So the correct answer is (c)