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The average of 41 numbers is 33. The average of the first 17 numbers is 41 and the average of the last 25 numbers is 27. Ifthe 17th number from the be
Question

The average of 41 numbers is 33. The average of the first 17 numbers is 41 and the average of the last 25 numbers is 27. Ifthe 17th number from the beginning is excluded, then what is the average of the remaining numbers?

A.

34.53

B.

30.1

C.

32.215

D.

33.35

Correct option is D

Given:

Total numbers = 41

Average of all 41 numbers = 33

Average of the first 17 numbers = 41

Average of the last 25 numbers = 27

The 17th number is excluded.

Formula Used:

Sum of observations = Average × Number of observations

Sum of remaining numbers = Total sum - 17th number

Solution:

Total sum of 41 numbers:

Total sum = 33 × 41 = 1353

Sum of the first 17 numbers:

Sum of first 17 = 41 × 17 = 697

Sum of the last 25 numbers:

Sum of last 25 = 27 × 25 = 675

The 17th number is common to both the first 17 and last 25 numbers.

Let the 17th number be x

Total sum = Sum of first 17 + Sum of last 25 - x

1353 = 697 + 675 - x

1353 = 1372 - x

x = 1372 - 1353

x = 19

Sum of the remaining numbers after excluding the 17th number:

Sum of remaining numbers = 1353 - 19 = 1334

Number of remaining numbers = 40

New Average = 133440\frac{1334}{40}​ = 33.35

Thus, The average of the remaining numbers is 33.35 

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