The areas of two squares are in the ratio 16 : 9. Find the ratio of their respective perimeters.

Correct option is A

Given:

The areas of two squares are in the ratio 16 : 9.

Formula Used:

Area of square = (side of square)$$^2$$ 

Solution:

Let side of first  square =A

Let side of second square =a

According to question

$$A^2:a^2$$​ = 16 : 9.

A:a= 4:3