​The amino acid arginine is encoded by six codons: CGU, CGC, CGA, CGG, AGA, and AGG. Assuming inosine is not an option in the tRNA anticodon, what is the minimum number of tRNAs that would be sufficient to read these codons?​

Correct option is C

Explanation-

Codon-Anticodon pairing:
                   Codons are read 5′→3′.
                   Anticodons pair 3′→5′ (antiparallel).
                   Wobble base pairing is allowed only at the third codon position (i.e., first base of the anticodon).
Wobble rules (without inosine):
                   1.  G in anticodon can pair with C or U in codon.
                   2.  U in anticodon can pair with A or G in codon.
                   3.  A, C, and G pair strictly with U, G, and C respectively.

Group 1: CGU & CGC
             Codons end in U and C.
             G in the first position of the anticodon can read both U and C.
So, 1 tRNA with anticodon 3′-GCI-5′ (but without inosine, just G for wobble). 1 tRNA can read both CGU & CGC.

Group 2: CGA & CGG
              Ends in A and G.
              U in anticodon can pair with both A and G.
              1 tRNA can read CGA & CGG.

Group 3: AGA & AGG
              Ends in A and G.
             1 tRNA for both AGA & AGG.

Minimum tRNAs Required:
          1 for CGU/CGC
          1 for CGA/CGG
          1 for AGA/AGG
Total = 3 tRNAs

 So, the correct answer is option C - Three