Solution:
Ten years ago, let the age of mother and her son be 3x and x respectively
According to the question
=> 3x + 20 = 2x + 40
=> x = 20
Present age of mother = 3 × 20 + 10 = 70 years
Present age of her son = 1 × 20 + 10 = 30 years
∴ Present age ratio of mother to her son = 70 : 30 = 7 : 3
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90 Mins English English100 Questions100 Marks90 Mins English English40 Questions30 Marks25 Mins EnglishIf 5 times a son's age is added to his father's age, the sum is 42 years. If 2.8 times the father's age is added to the son's age, the sum is 76 years. What is the father's age (in years)?
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Six times the present age of P exceeds the present age of Q by 46 years. After 10 years, six times Q’s age will be 18 years less than five times P’s age at that time. What is the present age of Q (in years)?
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The present ages of A and B are in the ratio 4 : 3 respectively. Three years ago, the ratio of their ages was 7 : 5. Find the age of A after 4 years from now (in years).
If 5 times a son’s age is added to his father’s age, the sum is 79 years. If 2.5 times the father’s age is added to the son’s age, the sum is 94 years. What is the father’s age (in years)?
If 2 times Mary's present age is 27 years more than 5 times Dia's present age, and 7 times Dia's present age is 9 years less than Mary's present age, then what is the difference (in years) between the ages of Mary and Dia?
3 years ago, a father's age was 24 years more than twice his son's age. After how many years from now will his age be twice his son's age?
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