T1 and T2 are the third proportional to 16, 36 and 24, 60, respectively. Find the ratio of T1 to T2.
Given:
First set of values: 16, 36
Second set of values: 24, 60
Formula Used:
If a, b, c are in proportion, then b2 = a × c
Solution:
T1 = (362) ÷ 16
T1 = 1296 ÷ 16
T1 = 81
T2 = (602) ÷ 24
T2 = 3600 ÷ 24
T2 = 150
Ratio of T1 to T2 = 81 : 150 = 27 : 50
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