If the third proportional of 4 and 16 be x, then what is the value of x?​

Correct option is D

Given:

The third proportional of 4 and 16 is x

Formula Used:

If a, b, c are in proportion, then

a : b = b : c

c = $$\frac{b^2}{a}$$​​

Solution:

Here, a = 4, b = 16

x = $$\frac{16^2}{4} = \frac{256}{4}$$​ = 64