Correct option is B
Given:
1) 62% officers are punctual (P)
P = a + g + d + f = 62%
2) 58% officers are honest (H)
H = b + g + d + e = 58%
3) 70% officers are brave (B)
B = c + f + d + e = 70%
4) 38% officers are punctual (P) and honest (H)
g + d = 38%
5) 48% are honest (H) and brave (B)
e + d = 48%
6) 36% are punctual (P) and brave (B)
f + d = 36%

Solution:
We know that,
100% = [P + H + B] – [(g +d) + (e +d) + (f +d)] + d
100% = [62% + 58% + 70%] – [(38%) + (48%) + (36%)] + d
100% = 190% - 122% + d
100% = 68% + d
d = 100% - 68%
d = 32%
Hence,
‘32%’ percentage of the officers are punctual (P), honest (H) and brave (B)