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    Solve the following.​4+3×3−24−3×(3−2)=?\frac{4+3×3-2}{4-3×(3-2)}=?4−3×(3−2)4+3×3−2​=?​​
    Question

    Solve the following.

    4+3×3243×(32)=?\frac{4+3×3-2}{4-3×(3-2)}=?​​

    A.

    12

    B.

    2

    C.

    11

    D.

    10

    Correct option is C

    Given:

    4+3×3243×(32)\frac{4+3×3-2}{4-3×(3-2)}

    Solution:

    4+3×3243×(32)\frac{4+3×3-2}{4-3×(3-2)}

    =4+9243×1\frac{4+9-2}{4-3×1}​​

    =13243\frac{13-2}{4-3} =11​

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