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Solve the following.​4+3×3−24−3×(3−2)=?\frac{4+3×3-2}{4-3×(3-2)}=?4−3×(3−2)4+3×3−2​=?​​
Question

Solve the following.

4+3×3243×(32)=?\frac{4+3×3-2}{4-3×(3-2)}=?​​

A.

12

B.

2

C.

11

D.

10

Correct option is C

Given:

4+3×3243×(32)\frac{4+3×3-2}{4-3×(3-2)}

Solution:

4+3×3243×(32)\frac{4+3×3-2}{4-3×(3-2)}

=4+9243×1\frac{4+9-2}{4-3×1}​​

=13243\frac{13-2}{4-3} =11​

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