Correct option is CGiven:4+3×3−24−3×(3−2)\frac{4+3×3-2}{4-3×(3-2)}4−3×(3−2)4+3×3−2Solution:4+3×3−24−3×(3−2)\frac{4+3×3-2}{4-3×(3-2)}4−3×(3−2)4+3×3−2=4+9−24−3×1\frac{4+9-2}{4-3×1}4−3×14+9−2=13−24−3\frac{13-2}{4-3}4−313−2 =11