Solve the following.

​$$3.\overline{36}-2.\overline{05}+1.\overline{33}=$$ ?​

Correct option is B

Given:

​$$3.\overline{36}-2.\overline{05}+1.\overline{33}$$

Concept Used:

​$$a.\overline {bc}=a+\frac{bc}{99}$$

Solution:

​$$3.\overline{36}-2.\overline{05}+1.\overline{33}$$

= 3 + $$\frac {36}{99}$$ - 2 - $$\frac{5}{99}$$ + 1 + $$\frac{33}{99}$$

= 2 + $$\frac{36-5+33}{99}$$

= 2 + $$\frac{64}{99}$$

= $$2.\overline {64}$$​​