Correct option is DGiven:0.12ˉ−0.6ˉ+0.3ˉ0.\bar{12 }- 0.\bar6 + 0.\bar30.12ˉ−0.6ˉ+0.3ˉ Concept Used:0.abcˉ=abc−bc9000.ab\bar c= \frac{abc - bc }{900}0.abcˉ=900abc−bc 0.1ˉ2−0.6ˉ+0.3ˉ0.\bar12 - 0.\bar6 + 0.\bar30.1ˉ2−0.6ˉ+0.3ˉ =1299−69+39= \frac{12}{99} - \frac{6}{9} + \frac{3}{9}=9912−96+93 = 12−66+3399\frac{12 - 66 + 33}{99}9912−66+33 = −2199\frac{-21}{99}99−21 = −733\frac{-7}{33}33−7