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    ​Solve :​(110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0
    Question

    ​Solve :

    (110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10​​

    A.

    100

    B.

    110

    C.

    105

    D.

    90

    Correct option is C

    Given: 

    (110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10 

    Concept Used: 

    Operation preference wise

    Symbol

    Brackets

    [], {}, ()

    Orders, of

    x (power), √ (root), of

    Division

    ÷

    Multiplication

    ×

    Addition

    +

    Subtraction

    -

    Solution: 

    (110÷16100)  of  3.20.4+120÷4 of 3×10 =(1016)  of  3.20.4+120÷4 of 3×10 =5+120÷12×10 =5+10×10 =5+100 =105\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10 \\ \ \\ =\left( \frac{10}{16} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10\\ \ \\= 5 + 120 \div 12 \times 10 \\ \ \\ = 5+10\times 10 \\ \ \\ = 5 + 100 \\ \ \\ = 105​​

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