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​Solve :​(110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0
Question

​Solve :

(110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10​​

A.

100

B.

110

C.

105

D.

90

Correct option is C

Given: 

(110÷16100)  of  3.20.4+120÷4 of 3×10\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10 

Concept Used: 

Operation preference wise

Symbol

Brackets

[], {}, ()

Orders, of

x (power), √ (root), of

Division

÷

Multiplication

×

Addition

+

Subtraction

-

Solution: 

(110÷16100)  of  3.20.4+120÷4 of 3×10 =(1016)  of  3.20.4+120÷4 of 3×10 =5+120÷12×10 =5+10×10 =5+100 =105\left( \frac{1}{10} \div \frac{16}{100} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10 \\ \ \\ =\left( \frac{10}{16} \right)\ \text{ of }\ \frac{3.2}{0.4} + 120 \div 4\ \text{of}\ 3 \times 10\\ \ \\= 5 + 120 \div 12 \times 10 \\ \ \\ = 5+10\times 10 \\ \ \\ = 5 + 100 \\ \ \\ = 105​​

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