Correct option is C
Given:
4101−[221−{65−(52+103)}]
Concept Used:
BODMAS rule:
Operation preference wiseBracketsOrders,ofDivisionMultiplicationAdditionSubtractionSymbol[],,()x(power),√(root),of÷×+−
Solution:
4101−[221−{65−(52+103)}] =1041−[25−{65−(107)}] =1041−[25−{304}] =1041−3071 =3052=1526