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Simplify:​645÷[414÷{513×38+(312+23)×45}]6\frac{4}{5}÷[4\frac{1}{4}÷\{5\frac{1}{3}×\frac{3}{8} + (3\frac{1}{2}+\frac{2}{3})×\frac{4}{5}\}]654​÷[441​÷{5
Question

Simplify:

645÷[414÷{513×38+(312+23)×45}]6\frac{4}{5}÷[4\frac{1}{4}÷\{5\frac{1}{3}×\frac{3}{8} + (3\frac{1}{2}+\frac{2}{3})×\frac{4}{5}\}]​​

A.

88158\frac{8}{15}​​

B.

78257\frac{8}{25}​​

C.

88258\frac{8}{25}​​

D.

78157\frac{8}{15}​​

Correct option is A

Given: 
To find: value of 645÷[414÷{513×38+(312+23)×45}]6\frac{4}{5}÷[4\frac{1}{4}÷\{5\frac{1}{3}×\frac{3}{8} + (3\frac{1}{2}+\frac{2}{3})×\frac{4}{5}\}] 
Concept Used: 
BODMAS rule:
Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}    
Solution:
   645÷[414÷{513×38+(312+23)×45}] =345÷[174÷{163×38+(72+23)×45}] =345÷[174÷{2+(256)×45}] =345÷[174÷{2+(103)] =345÷[174÷163] =345÷[174×316] =345÷5164 =345×6451=12815=88156\frac{4}{5}÷[4\frac{1}{4}÷\{5\frac{1}{3}×\frac{3}{8} + (3\frac{1}{2}+\frac{2}{3})×\frac{4}{5}\}]\\\ \\=\frac{34}{5}÷[\frac{17}{4}÷\{\frac{16}{3}×\frac{3}{8} + (\frac{7}{2}+\frac{2}{3})×\frac{4}{5}\}]\\\ \\=\frac{34}{5}÷[\frac{17}{4}÷\{2 + (\frac{25}{6})×\frac{4}{5}\}]\\\ \\=\frac{34}{5}÷[\frac{17}{4}÷\{2 + (\frac{10}{3})]\\\ \\=\frac{34}{5}÷[\frac{17}{4}÷\frac{16}{3}]\\\ \\=\frac{34}{5}÷[\frac{17}{4}×\frac{3}{16}]\\\ \\=\frac{34}{5}÷\frac{51}{64}\\\ \\=\frac{34}{5}× \frac{64}{51} = \frac{128}{15} = 8 \frac{8}{15}

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