Simplify: $$^6\sqrt{4096} + ^4\sqrt{4096} + ^3\sqrt{4096} + \sqrt{4096}$$​​

Correct option is A

Given: 

 $$^6\sqrt{4096} + ^4\sqrt{4096} + ^3\sqrt{4096} + \sqrt{4096}$$  

Concept Used:

$$2^{12} = 4096$$​

Solution: 

$$^6\sqrt{4096} + ^4\sqrt{4096} + ^3\sqrt{4096} + \sqrt{4096}$$ 

$$\begin{aligned}& \sqrt[6]{4096} + \sqrt[4]{4096} + \sqrt[3]{4096} + \sqrt{4096} \\&= 2^{\frac{12}{6}} + 2^{\frac{12}{4}} + 2^{\frac{12}{3}} + 2^{\frac{12}{2}} \\&= 2^2 + 2^3 + 2^4 + 2^6 \\&= 4 + 8 + 16 + 64 \\&= 92\end{aligned}$$​

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