Simplify :$$\frac {(1\frac14÷1 \frac12)}{(\frac1{15}+1-\frac9{10})}$$​​

Correct option is C

​$$\frac {(1\frac14÷1 \frac12)}{(\frac1{15}+1-\frac9{10})} \\\frac{\left(1 \frac{1}{4} \div 1 \frac{1}{2}\right)}{\left(\frac{1}{15} + 1 - \frac{9}{10}\right)}\\= \frac{\left(\frac{5}{4} \div \frac{3}{2}\right)}{\left(\frac{1}{15} + \frac{15}{15} - \frac{13.5}{15}\right)}\\= \frac{\frac{5}{6}}{\frac{1}{6}}\\= 5$$​​