Correct option is DGiven:1.8+2×32×12[25÷(35×23)×32−1]1.8 + 2 \times \frac{3}{2} \times \frac{1}{2}[ { \frac{2}{5} \div (\frac{3}{5} \times \frac{2}{3}) \times \frac{3}{2} - 1 }]1.8+2×23×21[52÷(53×32)×23−1] Solution:1.8+2×32×12[25÷(35×23)×32−1]1.8 + 2 \times \frac{3}{2} \times \frac{1}{2}[ { \frac{2}{5} \div (\frac{3}{5} \times \frac{2}{3}) \times \frac{3}{2} - 1 }]1.8+2×23×21[52÷(53×32)×23−1] =1.8+32[25÷(25)×32−1]1.8 + \frac{3}{2} [ { \frac{2}{5} \div (\frac{2}{5} ) \times \frac{3}{2} - 1 }]1.8+23[52÷(52)×23−1] =1.8+32[32−1]1.8 + \frac{3}{2} [ { \frac{3}{2} - 1 }]1.8+23[23−1] =1.8+32[12]1.8 + \frac{3}{2} [ { \frac{1}{2} }]1.8+23[21] =1.8+0.75=2.55