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    Select the combination of symbols that when sequentially placed in the blanks of the given equation will complete the equation. 9 _ 3 _ 0 _ 8 _ 2 =
    Question

    Select the combination of symbols that when sequentially placed in the blanks of the given equation will complete the equation.
    9 _ 3 _ 0 _ 8 _ 2 = 23

    A.

    ÷\div, +, -, ×\times

    ​​

    B.

    ×\times, +, -, ÷\div​​

    C.

    -, +, ÷\div, ×\times​​

    D.

    +, -, ×\times, ÷\div​​

    Correct option is B

    Given: 9 _ 3 _ 0 _ 8 _ 2 = 23
    Logic: Fill the symbols in the given blanks of the equation and then solve the equation using the BODMAS rule.
    Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{ | c | c | } \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[], {}, () \\ \hline Orders, of & (power), √ (root), of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​​
    Let's check the options:
    First option: ​​÷\div, +, -, ×\times
    The equation becomes, 9 ÷\div 3 + 0 - 8 ×\times 2 = 23
    =>\Rightarrow 3 + 0 - 8 ×\times 2 = 23
    =>\Rightarrow 3 + 0 - 16 = 23
    =>\Rightarrow 3 - 16 = 23
    =>\Rightarrow -13 \neq 23 (This option does not satisfy the equation.)
    Second option: ×\times, +, -, ÷\div
    The equation becomes, 9 ×\times 3 + 0 - 8 ÷\div 2 = 23
    =>\Rightarrow 9 ​×\times 3 + 0 - 4 = 23
    =>\Rightarrow 27 + 0 - 4 = 23
    =>\Rightarrow 23 = 23 (This option satisfies the equation.)
    Third option: -, +, ×\times, ÷\div
    The equation becomes, 9 - 3 + 0 ×\times 8 ÷\div 2 = 23​
    =>\Rightarrow 9 - 3 + 0 ×\times​ 4 = 23
    =>\Rightarrow 9 - 3 + 0 = 23
    =>\Rightarrow 6 \neq 23 (This option does not satisfy the equation.)
    Fourth option: +, -, ×\times, ÷\div
    The equation becomes, 9 + 3 - 0 ×\times 8 ÷\div 2 = 23
    =>\Rightarrow 9 + 3 - 0 ×\times​ 4 = 23
    =>\Rightarrow 9 + 3 - 0 = 23
    =>\Rightarrow 12 \neq​ 23 (This option does not satisfy the equation.)
    So, the correct answer is (b).

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