arrow
arrow
arrow
Select the combination of symbols that when sequentially placed in the blanks of the given equation will complete the equation. 9 _ 3 _ 0 _ 8 _ 2 =
Question

Select the combination of symbols that when sequentially placed in the blanks of the given equation will complete the equation.
9 _ 3 _ 0 _ 8 _ 2 = 23

A.

÷\div, +, -, ×\times

​​

B.

×\times, +, -, ÷\div​​

C.

-, +, ÷\div, ×\times​​

D.

+, -, ×\times, ÷\div​​

Correct option is B

Given: 9 _ 3 _ 0 _ 8 _ 2 = 23
Logic: Fill the symbols in the given blanks of the equation and then solve the equation using the BODMAS rule.
Operation preference wiseSymbolBrackets[],,()Orders,of(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin{array}{ | c | c | } \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline Brackets &[], {}, () \\ \hline Orders, of & (power), √ (root), of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​​
Let's check the options:
First option: ​​÷\div, +, -, ×\times
The equation becomes, 9 ÷\div 3 + 0 - 8 ×\times 2 = 23
=>\Rightarrow 3 + 0 - 8 ×\times 2 = 23
=>\Rightarrow 3 + 0 - 16 = 23
=>\Rightarrow 3 - 16 = 23
=>\Rightarrow -13 \neq 23 (This option does not satisfy the equation.)
Second option: ×\times, +, -, ÷\div
The equation becomes, 9 ×\times 3 + 0 - 8 ÷\div 2 = 23
=>\Rightarrow 9 ​×\times 3 + 0 - 4 = 23
=>\Rightarrow 27 + 0 - 4 = 23
=>\Rightarrow 23 = 23 (This option satisfies the equation.)
Third option: -, +, ×\times, ÷\div
The equation becomes, 9 - 3 + 0 ×\times 8 ÷\div 2 = 23​
=>\Rightarrow 9 - 3 + 0 ×\times​ 4 = 23
=>\Rightarrow 9 - 3 + 0 = 23
=>\Rightarrow 6 \neq 23 (This option does not satisfy the equation.)
Fourth option: +, -, ×\times, ÷\div
The equation becomes, 9 + 3 - 0 ×\times 8 ÷\div 2 = 23
=>\Rightarrow 9 + 3 - 0 ×\times​ 4 = 23
=>\Rightarrow 9 + 3 - 0 = 23
=>\Rightarrow 12 \neq​ 23 (This option does not satisfy the equation.)
So, the correct answer is (b).

Free Tests

Free
Must Attempt

CBT-1 Full Mock Test 1

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

RRB NTPC Graduate Level PYP (Held on 5 Jun 2025 S1)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

RRB NTPC UG Level PYP (Held on 7 Aug 2025 S1)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English

Similar Questions

test-prime-package

Access ‘RRB NTPC’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow