Raj invested ₹14,000 at 10% p.a. for 1 year at compound interest, compounded half-yearly. The amount received by him is:

Correct option is A

Given:

​$$P = 14,000 \quad$$

$$r = 10\% = 0.10$$

$$t$$ = 1 $$year$$ , $$n=$$$$2 \text{ (half-yearly)}$$​​​​

Formula Used:

Compound interest = $$P \left( 1 + \frac{r}{n} \right)^{n \cdot t}$$ 

Solution:

Substituting the values:

​$$A = 14000 \left( 1 + \frac{0.10}{2} \right)^{2 \cdot 1}$$ 

$$A = 14000 \left( 1 + 0.05 \right)^2$$ 

$$A = 14000 \times 1.05^2$$ 

$$A = 14000 \times 1.1025$$ 

$$A = ₹15,435$$ 

Thus the correct answer is (A)