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Rafique and Pritam invested identical sums of money for two years at interest rates that compound annually at 15% per annum and 10% per annum respecti
Question

Rafique and Pritam invested identical sums of money for two years at interest rates that compound annually at 15% per annum and 10% per annum respectively. If Rafique earns ₹2,250 more as interest than Pritam during these two years, then how much did each of them invest initially?

A.

₹18,000

B.

₹20,000

C.

₹20,250

D.

₹22,500

Correct option is B

Given:
Rafique and Pritam invested identical sums of money for 2 years.
Rafique's investment earns 15% per annum compounded annually.
Pritam's investment earns 10% per annum compounded annually.
Rafique earns ₹2,250 more as interest than Pritam during these two years.
We need to find the initial amount invested by each of them.
Formula Used:
Compound Interest Formula:
A =P(1+r100)t P \left(1 + \frac{r}{100}\right)^t​​
where:
A = Amount after t years
P = Principal amount

r = Annual interest rate
t  = Time in years
The interest earned is:
Interest=AP\text{Interest} = A - P
Solution:
Let the initial investment be  P .
Both Rafique and Pritam invested the same amount  P .
Calculate the amount for Rafique after 2 years
Rafique's interest rate = 15% per annum.
ARafique=P(1+15100)2=P(1.15)2=P×1.3225A_{\text{Rafique}} = P \left(1 + \frac{15}{100}\right)^2 = P (1.15)^2 = P \times 1.3225​​
Interest earned by Rafique:
InterestRafique=ARafiqueP=1.3225PP=0.3225P\text{Interest}_{\text{Rafique}} = A_{\text{Rafique}} - P = 1.3225P - P = 0.3225P​​
Pritam's interest rate = 10% per annum.
APritam=P(1+10100)2=P(1.10)2=P×1.21A_{\text{Pritam}} = P \left(1 + \frac{10}{100}\right)^2 = P (1.10)^2 = P \times 1.21​​
Interest earned by Pritam:
InterestPritam=APritamP=1.21PP=0.21P\text{Interest}_{\text{Pritam}} = A_{\text{Pritam}} - P = 1.21P - P = 0.21P​​
Rafique earns ₹2,250 more as interest than Pritam:
InterestRafiqueInterestPritam=2,250\text{Interest}_{\text{Rafique}} - \text{Interest}_{\text{Pritam}} = 2,250​​
0.3225P - 0.21P = 2,250
0.1125P = 2,250
P=2,2500.1125=20,000 = \frac{2,250}{0.1125} = 20,000
Each of them initially invested ₹20,000.

Alternate Method:
Let the initial investment be P .
Calculate the difference in interest earned:
P(1.1521)P(1.1021)=2,250P \left(1.15^2 - 1\right) - P \left(1.10^2 - 1\right) = 2,250​​
P (1.3225 - 1) - P (1.21 - 1) = 2,250
P (0.3225) - P (0.21) = 2,250
0.1125P = 2,250
P =2,2500.1125=20,000 \frac{2,250}{0.1125} = 20,000​​
Thus, each of them initially invested ₹20,000.

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