Radius of a sphere is increased by 50 percent. What will be the percentage increase in its volume?

Correct option is B

Given:
Initial Radius = r
Increased Radius = 1.5r
Formula Used:
Volume of sphere = 4/3πr³
Solution:
Let the radius be x
Vol. of sphere = 4/3πr³
ATQ
New radius = 50x/100 + x = 150x/100 = 1.5r
New vol. = $$\frac 43 \times \pi (1.5r)^3=\frac 43 \times \pi 3.375 \times r^3$$​​
$$\text {Change in Volume}= \frac{\frac 43 \times \pi 3.375 \times r^3 - \frac 43 \pi \times r^3}{\frac 43 \times \pi \times r^3}\\\text {Change in Volume}=\frac{ 3.375-1}{1} = 2.375$$​​​
Increase vol. in percentage =2.375$$\times$$​ 100 = 237.5%