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​Populations of two species (A and B) follow logistic growth. The parameter values for the logistic growth equation are given in the table below.​​Sel
Question

Populations of two species (A and B) follow logistic growth. The parameter values for the logistic growth equation are given in the table below.

Select the option that correctly gives the population growth rate at N = 100 for both species.

A.

Species A = 150; Species B = 82

B.

Species A = 200; Species B = 72

C.

Species A = 250; Species B = 46

D.

Species A = 300; Species B = 68

Correct option is B

EXPLANATION-

To solve this question on logistic population growth, we will use the logistic growth formula:

dNdt=rN(1NK)\frac{dN}{dt} = rN \left(1 - \frac{N}{K}\right)

Where:
r = intrinsic growth rate
N = current population size
K = carrying capacity
dNdt\frac{dN}{dt}​= population growth rate

Step 1: Calculate growth rate for Species A:

dNAdt=2.5×100×(1100500)\frac{dN_A}{dt} = 2.5 \times 100 \times \left(1 - \frac{100}{500}\right)=2.5×100×(10.2)=2.5×100×0.8=200= 2.5 \times 100 \times (1 - 0.2) = 2.5 \times 100 \times 0.8 = 200

​​​Step 2: Calculate growth rate for Species B:

dNBdt=0.8×100×(11001000)\frac{dN_B}{dt} = 0.8 \times 100 \times \left(1 - \frac{100}{1000}\right)=0.8×100×(10.1)=0.8×100×0.9=72= 0.8 \times 100 \times (1 - 0.1) = 0.8 \times 100 \times 0.9 = 72


so, the correct option is (b) - Species A = 200 , Species B = 72

​​

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