Person A tells the truth 30% of the times and B tells the truth 40% of the times, independently. What is the minimum probability that they would contradict each other?

Correct option is C

Given:
· Probability of A telling the truth = 0.3.
· Probability of B telling the truth = 0.4.
Formula: The probability of contradiction = P(A truth and B lie) + P(A lie and B truth).
Solution:
1. Probability that A tells the truth and B lies:

P(A truth and B lie) = 0.3 × (1 - 0.4) = 0.3 × 0.6 = 0.18
2. Probability that A lies and B tells the truth:

P(A lie and B truth) = (1 - 0.3) × 0.4 = 0.7 × 0.4 = 0.28
3. Total probability of contradiction:

P(contradiction) = 0.18 + 0.28 = 0.46
Final Answer: (c) 0.46