Correct option is C
P, Q and R can individually do a work in 10, 12 and 15 days respectively. They start working together and P leaves after 2 days. Q left 3 days before completion of work. In how many days was the work completed?
Solution:
Let the total work = LCM of (10, 12, 15) = 60
Then the efficiency of P = 60/10 = 6 unit/day
The efficiency of Q = 60/12 = 5 unit/day
The efficiency of R = 60/15 = 4 unit/day
The work done by (P+Q+R) in 2 days = (6+5+4)2 = 30 unit
The work one by Q in three days = 3 5 = 15 unit
Then the Remaining work done R and Q = 45/9 = 5 days
Total days = 5 + 2 = 7 days.