Number A is eight times as large as number B. By what percentage is number B less than number A?

Correct option is A

Given:
A = 8 × B

Concept Used:
Percentage decrease = $$[\frac{(Difference) }{ (Original\ Value)}] × 100$$ 

Solution:

Let the value of B = x
Then, A = 8x

Difference = A - B = 8x - x = 7x

Percentage by which B is less than A = $$(\frac{7x }{ 8x}) × 100$$​​

Percentage = $$(\frac{7 }{ 8}) × 100 = 87.50 \%$$​​