Nine years ago, P's age was twice the age of Q. If the ratio of their present ages is 5 : 4, what is the sum of their present ages?

Correct option is B

Given:

Nine years ago, P's age was twice Q's age.

The ratio of their present ages is 5:4.

Find the sum of their present ages.

Formula Used:

Present Age – 9 = Age 9 years ago

Solve the equation to find x, then calculate the sum of present ages.

Solution:

Let the present ages of P and Q be 5x and 4x respectively.

Nine years ago, P's age was 5x−95 Q's age was 4x−9 From the given condition:

5x – 9 = 2(4x−9)

5x – 9 = 8x – 18

18 – 9 = 8x – 5x

9 = 3x

x = 3 

Total present age = 5x + 4x = 9x 

Putting the value; 

= 9$$\times$$3 = 27 years