Mr. X distributed some money among his wife, two sons and one daughter and also kept some money for himself. 20% of the total money that he had, he gave to his wife and kept 22% of it for himself. 60% of the remaining money he distributed among his two sons and gave the remaining to his daughter. If the daughter got 2,940 more money, he kept for himself, then what was the total money that he distributed among his sons?

Correct option is A

Given:
Total money given to wife = 20% of the total amount.
Amount kept for self = 22% of the total amount.
60% of the remaining money is distributed among two sons, and the rest is given to the daughter.
Daughter received an extra amount than the son = Rs. 2940
Solution:
Let the total amount distributed be Rs. x.
Money given to wife: $$\frac{20}{100} \times x = 0.2x$$​

Money kept for self: $$\frac{22}{100} \times x = 0.22x$$​
Amount left: x - 0.2x - 0.22x = 0.58x
Money given to sons: $$\frac{60}{100} \times 0.58x = 0.348x$$​
Amount left for daughter: 0.58x - 0.348x = 0.232x
As per the question:
0.232x - 0.22x = 2940
Simplify:
0.012x = 2940
​$$x = \frac{2940}{0.012} = \text{Rs } 245,000$$​​
Money given to sons: 0.348 × 245000 = Rs. 85,260

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