May of light in air is incident at an angle of 60° on the surface separating air from a medium of refractive index . The my is refracted in the medium at an angle of __________.

Correct option is C

Correct Answer: C 30°

Explanation:
To find the refracted angle when light passes from air (refractive index n₁ = 1) to a medium with refractive index n₂, we use Snell’s Law:

​$$n₁ \sin \theta_1 = n₂ \sin \theta_2$$​​

where:

• n₁ = 1 (Refractive index of air)
• θ₁=60^∘ (Angle of incidence)
• n₂=2 (Refractive index of the medium)
• θ₂​ (Angle of refraction, to be determined)

Using Snell's Law:

​$$1 \times \sin 60^\circ = 2 \times \sin \theta_2 \ \\\frac{\sqrt{3}}{2} = 2 \sin \theta_2\ \\ \sin \theta_2 = \frac{\sqrt{3}}{4}$$​​

Using standard trigonometric values, we get:

θ₂=30^∘

Thus, the refracted angle is 30°.

Information Booster:

• Snell’s Law states that the ratio of sine of angles is equal to the inverse ratio of refractive indices.
  
• When light moves from a rarer to a denser medium, it bends towards the normal.
  
•  When light moves from a denser to a rarer medium, it bends away from the normal.
  
•  If the incident angle is large enough, total internal reflection occurs instead of refraction.
  
•  The critical angle is the angle of incidence beyond which light gets totally reflected inside the medium.