Let G be a group of order 2020 .

Which of the following statements are necessarily true?

Correct option is A

| G | = 2020= $$2^2 \times 5 \times 101$$ .

Now, 101 divides 2020 but $$101^2$$ does not divide 2020 .

$$\implies$$ G has a p-subgroup of order 101.

and , from sylow's third theorem there will be unique subgroup of order 101

and that subgroup will be normal.

Hence , G is not simple group.

​$$\implies \textbf{Option A is correct}$$

The fact that the order of $G$ is composed of multiple prime factors does not necessarily imply that $G$ is abelian.

and Non-abelian $$\implies$$Non-Cyclic  $$\implies$$there can be more then 4 proper subgroups.​