Given:
LCM of two numbers = 154
HCF of two numbers = 7
One of the numbers = 77
Formula Used:
Product of two numbers = LCM × HCF
Solution:
Let the two numbers be 'a' and 'b'.
We are given that a = 77
Let the other number be 'b'.
Using the formula, a × b = LCM × HCF
77 × b = 154 × 7
b =
b = 14
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Three bells start ringing after interval of 20 minutes, 25 minutes and 40 minutes. They ringsimultaneously at 8: 00 am. They will ring simultaneously again at :
The largest four-digit number which when divided by 9, 18 and 23, leaves a remainder 5 in each case, is:
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The LCM of 44, 32, 176 and 352 is:
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