Three persons step out together for a walk. Their steps measure 90 cm, 95 cm and 75 cm, respectively. What is the minimum distance (in m) each should walk so that they can cover the distance in complete step?

Correct option is D

Given:
Person 1 step length = 90 cm
Person 2 step length = 95 cm
Person 3 step length = 75 cm
Formula Used:
To find the minimum distance, calculate the LCM (Least Common Multiple) of the step lengths in cm, and convert it to meters.
Solution:
Factor of 90 = $$2 \times 3^2 \times 5$$
Factor of 95 = $$19 \times 5$$
Factor of 75 = $$5^2 \times 3$$​​
The LCM of 90, 95, and 75 = $$2 \times 3^2 \times 5^2 \times 19 = 8550$$, which is equivalent to 85.5 meters.