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L.C.M. of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M. is 403. If one of the numbers is 124, then find the other number.
Question

L.C.M. of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M. is 403. If one of the numbers is 124, then find the other number.

A.

112

B.

76

C.

64

D.

93

Correct option is D

Given:
L.C.M. of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M. is 403.
One number is 124.
Formula Used:
LCM × HCF of two numbers = Product of those two numbers
Solution:
Let, the HCF of two number be x
=> LCM of those two number is 12x
Sum of H.C.F. and L.C.M. = 403
x + 12x = 403
=> 13x = 403
=> x = 31
HCF of those two number is 31 and LCM = 31 × 12
Let, the other number be b
Now, LCM × HCF = Product of two numbers
=> 31 × 31 × 12 = 124 × b
=> b = 93
∴ The other number is 93.

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