Correct option is D
Given:
L.C.M. of two numbers is 12 times their H.C.F. The sum of H.C.F. and L.C.M. is 403.
One number is 124.
Formula Used:
LCM × HCF of two numbers = Product of those two numbers
Solution:
Let, the HCF of two number be x
=> LCM of those two number is 12x
Sum of H.C.F. and L.C.M. = 403
x + 12x = 403
=> 13x = 403
=> x = 31
HCF of those two number is 31 and LCM = 31 × 12
Let, the other number be b
Now, LCM × HCF = Product of two numbers
=> 31 × 31 × 12 = 124 × b
=> b = 93
∴ The other number is 93.