Correct option is D
Given:
From condition (i):
If the first element is an odd number and the last element is an even number, their codes are to be interchanged.
Here, 5 (C) is odd (first element), and 8 (U) is even (last element).
Interchange C and U:
The sequence becomes: C T D S A T K U
Interchange C and U:
The sequence becomes: C T D S A T K U
From condition (ii):
If the second element is a symbol and the fifth element is an even number, their codes are to be interchanged.
Here, # (T) is a symbol (second element), and 7 (A) (fifth element) is odd, not even.
This condition does not apply.
This condition does not apply.
From condition (iii):
If the third element is a number and the fourth element is a symbol, both are coded as W.
Here, % (D) is a symbol (third element), and 6 (S) is a number (fourth element).
Both are coded as W.
The sequence becomes: U T W W A T K C
Both are coded as W.
The sequence becomes: U T W W A T K C
Here the sequence is:
After applying all the conditions, the final coded sequence is:
C T D S A T K U
C T D S A T K U
Thus, correct option is (d).
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