hamburger menu
All Coursesall course arrow
adda247
reward-icon
adda247
    arrow
    arrow
    arrow
    In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combinat
    Question

    In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.
    Number/Symbol
    6
    #
    4
    9
    @
    %
    >
    2
    !
    ?
    5
    8
    $
    3
    Code
    C
    H
    T
    J
    D
    G
    M
    X
    V
    W
    K
    U
    N
    L
    Conditions:
    (i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.
    (ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as £.
    (iii)If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
    How will $#94@3 be coded?​​

    A.

    NH J T D L

    B.

    L H J T D N

    C.

    LH D T G N

    D.

    £HJ T D£

    Correct option is B

    Given :
    Number/Symbol
    6
    #
    4
    9
    @
    %
    >
    2
    !
    ?
    5
    8
    $
    3
    Code
    C
    H
    T
    J
    D
    G
    M
    X
    V
    W
    K
    U
    N
    L
    ​$#94@3
    Condition (i):  The first element is a symbol ($)  and the last is a Number (3), the codes for the first and last are interchanged :  
    Interchanged(3= N and $=L)
    Condition (ii):  The first element is an odd number and the last is a even number, the first and last elements are coded as Does not apply because the first element is now a symbol (L), not an odd number.
    Condition (iii). if both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
    The second (#) and third (=) elements are perfect squares, the third element is coded as the code for the second element. Does not apply because = is not a number , and # is not a perfect square. 
    Now code of $#94@3 is LHJTDN
    Thus, correct option is (b).

    Free Tests

    Free
    Must Attempt

    CBT-1 Full Mock Test 1

    languageIcon English
    • pdpQsnIcon100 Questions
    • pdpsheetsIcon100 Marks
    • timerIcon90 Mins
    languageIcon English
    Free
    Must Attempt

    RRB NTPC Graduate Level PYP (Held on 5 Jun 2025 S1)

    languageIcon English
    • pdpQsnIcon100 Questions
    • pdpsheetsIcon100 Marks
    • timerIcon90 Mins
    languageIcon English
    Free
    Must Attempt

    RRB NTPC UG Level PYP (Held on 7 Aug 2025 S1)

    languageIcon English
    • pdpQsnIcon100 Questions
    • pdpsheetsIcon100 Marks
    • timerIcon90 Mins
    languageIcon English

    Similar Questions

    test-prime-package

    Access ‘RRB Group D’ Mock Tests with

    • 60000+ Mocks and Previous Year Papers
    • Unlimited Re-Attempts
    • Personalised Report Card
    • 500% Refund on Final Selection
    • Largest Community
    students-icon
    368k+ students have already unlocked exclusive benefits with Test Prime!
    Our Plans
    Monthsup-arrow