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In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combinat
Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the condition is your answer.
Number/Symbol
6
#
4
9
@
%
>
2
!
?
5
8
$
3
Code
C
H
T
J
D
G
M
X
V
W
K
U
N
L
Conditions:
(i) If the first element is a symbol and the last, a number, the codes for these two are to be interchanged.
(ii) If the first element is an odd number and the last, an even number, the first and last elements are to be coded as £.
(iii)If both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
How will $#94@3 be coded?​​

A.

NH J T D L

B.

L H J T D N

C.

LH D T G N

D.

£HJ T D£

Correct option is B

Given :
Number/Symbol
6
#
4
9
@
%
>
2
!
?
5
8
$
3
Code
C
H
T
J
D
G
M
X
V
W
K
U
N
L
​$#94@3
Condition (i):  The first element is a symbol ($)  and the last is a Number (3), the codes for the first and last are interchanged :  
Interchanged(3= N and $=L)
Condition (ii):  The first element is an odd number and the last is a even number, the first and last elements are coded as Does not apply because the first element is now a symbol (L), not an odd number.
Condition (iii). if both second and third elements are perfect squares, the third element is to be coded as the code for the second element.
The second (#) and third (=) elements are perfect squares, the third element is coded as the code for the second element. Does not apply because = is not a number , and # is not a perfect square. 
Now code of $#94@3 is LHJTDN
Thus, correct option is (b).

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