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In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combinat
Question

In this question, a group of numbers/symbols is coded using letters as per the table given below and the conditions which follow. The correct combination of codes following the conditions is your answer.
Number/Symbol
22
56
33
#
46
&
64
@
%
37
57
Code
L
K
J
H
G
F
D
S
A
P
B
Conditions:
(i) If the first element is a symbol and the last element is a number, then replace these two (first and last) elements with %.
(ii) If the second element is a number and the second last is a symbol, the codes of the first and last elements are to be interchanged.
(iii) If the question has an equal quantity of even and odd numbers, then replace the even numbers with * and odd numbers with <
Question: # 22 64 % 33 & 37 @

A.

H**A<F<S

B.

HLDAJFPS

C.

H**A33F37S

D.

#LDAJFP@

Correct option is A

According to the given information:
Number/Symbol
22
56
33
#
46
&
64
@
%
37
57
Code
L
K
J​
H
G
F
D
S
A
P
B
the given code is : # 22 64 % 33 & 37 @
​Conditions:
(i) If the first element is a symbol and the last element is a number, then replace these two (first and last) elements with %.
​The first element is # (a symbol) and the last element is @ (a symbol), so this condition does not apply.
(ii): If the second element is a number and the second last is a symbol, the codes of the first and last elements are to be interchanged.
​The second element is 22(a number) and the second last element is 37 (a number), so this condition does not apply.
(iii): If the question has an equal quantity of even and odd numbers, then replace the even numbers with * and odd numbers with <
​Even numbers: 22, 64
Odd numbers: 33, 37
We have 2 even numbers and 2 odd numbers, so we replace even numbers with * and odd numbers with <
Final Combination of Codes:
H**A<F<S
So, the correct combination of codes following the given conditions is H * * A < F < S.
Thus, correct answer is (a) H * * A < F < S.

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