In this question, a group of numbers/symbols is coded using letters as per the table below and the following conditions. The correct combination of codes following the conditions is your answer.

​Conditions:

(i) If the first element is an odd number and the last element is an even number, the codes for these two (the first and the last elements) are to be interchanged.

(ii) If the second element is a symbol and the fifth element is an even number, the codes for these two (the second and the fifth elements) are to be interchanged.

(iii) If the third element is a number and the fourth element is a symbol, both these elements (the third and the fourth elements) are to be coded as Y.

Question: 6 # % 3 8 5 # 4

The given question that is to be coded is as follows: 6 # % 3 8 5 # 4

Now, let's check the conditions:

(i) If the first element is an odd number and the last element is an even number: This condition does not follow.

(ii) If the second element is a symbol and the fifth element is an even number: This condition follows.

(iii) If the third element is a number and the fourth element is a symbol: This condition does not follow.​

It is clear that the second condition is satisfied. So, to code the given question, we need to interchange the codes for the second and fifth elements.

Therefore, '6 # % 3 8 5 # 4' is coded as 'R B K W P G P U'.

So, the correct answer is (c).