In the given reaction, which substance is insoluble?

​$$2\text{KBr}+\text{Bal}_2→\text{2KI}+\text{BaBr}_2$$​​

Correct option is B

The correct answer is (B) ​BaBr₂.

In the reaction $$2KBr+Bal_2→2KI + BaBr_2$$​ barium bromide (BaBr₂) is insoluble in water and forms a solid.

Explanation

• In this chemical reaction, potassium bromide (KBr) and barium iodide (Bal₂) react to form potassium iodide (KI) and barium bromide (BaBr₂)
• The equation is balanced because the number of atoms of each element is the same on both sides of the equation. 
• BaBr₂ is a white solid that is soluble in water, but it is toxic in aqueous form.