In how many years will ₹50,000 become ₹66,550 at 10% compound interest per annum?

Correct option is D

Given:

Principal P = ₹50,000
Amount A = ₹66,550
Rate R = 10% per annum (compound interest)

Formula Used:
A = P(1 +$$R)^{t}$$​​
Solution:
​$$66{,}550 = 50{,}000(1.1)^{t}$$​​

​$$\frac{66{,}550}{50{,}000} = 1.331 = (1.1)^t$$

$$(1.1)^3 = (1.1)^t$$​​​

Thus,
t = 3 years