In how many years will ₹2,500 be invested at the rate of 12% per annum simple interest, which amounts to ₹4,900?

Correct option is C

Given:
Principal P = ₹2500
Amount A = ₹4900
Rate of Interest R = 12% per annum
T = ?
Formula Used:
Simple Interest = $$\frac{P \times R \times T}{100}$$​​

A = P + Simple Interest

A = $$P + \frac{P \times R \times T}{100}$$​​

A = $$P \left( 1 + \frac{R \times T}{100} \right)$$

Where,

P = Principal, A = Amount R = Rate, T = Time

Solution: 

Applying the formula; 

4900 = $$2500 \left( 1 + \frac{12 \times T}{100} \right)$$​

4900 = $$2500 \left( 1 + \frac{12T}{100} \right)$$​

4900 = $$2500 + 2500 \times \frac{12T}{100}$$ 

4900 - 2500 = $$2500 \times \frac{12T}{100}$$​

2400 = $$2500 \times \frac{12T}{100}$$​

T = $$\frac{2400}{300} = 8$$​

The time required is 8 years.

Thus, the correct option is (c) 8 years

Alternate Method:

R = 12 % 

Principal : Amount

2500       : 4900

SI = 2400

Time = $$\frac{2400 \times 100}{2500 \times 12}$$ = 8 years ​