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In case of natural no. m attributes, the total number of ultimate class frequencies is :
Question

In case of natural no. m attributes,
the total number of ultimate class
frequencies is :

A.

2m

B.

2m–1

C.

2m+1

D.

m

Correct option is A

The correct answer is (a).

Introduction 

In the statistical theory of attributes, data is classified based on the presence or absence of specific qualitative characteristics.

When evaluating multiple attributes simultaneously, the data is divided into various classes.

The term "ultimate class frequencies" refers to the frequencies of classes of the highest order, determining the combinatorial capacity of the dataset.

Information Booster
  • An attribute denotes a qualitative characteristic (e.g., literacy, gender, employment status).
  • If we have $m$ distinct attributes, each attribute can exist in two states: present or absent.
  • The classes of the highest order, which specify the presence or absence of every single one of the m attributes, are called the ultimate classes.
  • Since each of the m attributes has 2 mutually exclusive states, the number of combinations is a power of 2.
  • Therefore, mathematically, the total number of ultimate class frequencies is given by 2m2^m​ (represented as 2m in plain text formatting here).
  • The total number of all class frequencies of all orders combined (from order 0 to order m) is given by 3m3^m.​
Additional Knowledge
  • Option B (2m–1): This implies 2m12^{m-1}​, which would mathematically represent the number of ultimate classes if one specific attribute were fixed or excluded, which is incorrect for the entire set of m attributes.
  • Option C (2m+1): This represents 2m+12^{m+1}​, which implies an analysis of m+1 attributes rather than m attributes.
  • Option D (m): This simply states the number of attributes themselves, not the combinatorial frequencies resulting from their presence/absence states.

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