Correct option is D
Correct answer is D
Explanation:
Increasing the frequency of the light while keeping its intensity constant impacts the photoelectric effect:
· Higher frequency photons have greater energy (E = hν).
· When the energy of the photons exceeds the work function, the excess energy is converted into the kinetic energy of the ejected electrons.
· Thus, increasing the frequency raises the kinetic energy of the electrons, leading to an increase in the stopping potential.
· Since the intensity of the light is kept constant, the number of photons remains the same, and hence the photoelectric current and saturation current do not change.
Therefore, the stopping potential increases, but the photoelectric current and saturation current remain unchanged.