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In an examination. the highest score and the lowest score differed by 55 and the higher one was 9/4 times the lower one. What is the lowest score?
Question

In an examination. the highest score and the lowest score differed by 55 and the higher one was 9/4 times the lower one.
What is the lowest score?

A.

44

B.

36

C.

40

D.

48

Correct option is A

Let the lowest score be x. According to the question, the highest score is94x \frac{9}{4}x​. It is also given that the difference between the highest and the lowest scores is 55. Therefore,
94xx=55.\frac{9}{4}x - x = 55.
Factor out x:
(941)x=5594x44x=54x=55.\left(\frac{9}{4} - 1\right) x = 55 \quad \Longrightarrow \quad \frac{9}{4}x - \frac{4}{4}x = \frac{5}{4}x = 55.
Solving for x yields
x=55×45=44.x = \frac{55 \times 4}{5} = 44.

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