In a triangle ABC, incenter is at O. Find angle BAC if angle BOC=110°.

​$$\angle BOC = 110^\circ$$​​

O is the incentre of the triangle.

In any triangle, the angle formed by the lines from the incentre to the vertices B and C ( $$\angle BOC$$​) is given by the following formula:

​$$\angle BOC = 90^\circ + \frac{1}{2} \angle A$$​​

where$$\angle A$$​ is the angle at vertex A (i.e., $$\angle BAC$$​).

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